(1/3)^(2x+3)=x+5

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Solution for (1/3)^(2x+3)=x+5 equation: 



(1/3)^(2x+3)=x+5

We move all terms to the left:

(1/3)^(2x+3)-(x+5)=0



Domain of the equation: 3)^(2x+3)!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^(2x+3)-(x+5)=0

We get rid of parentheses

(+1/3)^(2x+3)-x-5=0

We multiply all the terms by the denominator


(+1-x*3)^(2x+3)-5*3)^(2x+3)=0

We add all the numbers together, and all the variables

(-x*3+1)^(2x+3)-5*3)^(2x+3)=0

We add all the numbers together, and all the variables

(-x*3+1)^(2x+3)-5*3)^(2x=0

Wy multiply elements

(-x*3+1)^(2x+3)-15x=0

We add all the numbers together, and all the variables

-15x+(-x*3+1)^(2x+3)=0

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